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\sum_{k=1}^{5}k^{2}
#Just write down the final value
\sum_{k=1}^{3}(2k)^{2}
# Just write the final value
\sum_{n=1}^{4}(-1)^{n}n
# Just right down the final value
\sum_{k=0}^{5}2^{k}
#Just right down the final value
Use the geometric definition of the definite integral to compute:
\int_{-1}^{2} |x|dx
View the complete course at: http://ocw.mit.edu/18-01F06 Lecture 17 is Exam 2, so no video was recorded. License: Creative Commons BY-NC-SA More information at http://ocw.mit.edu/terms More courses at http://ocw.mit.edu
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